Percentage Questions and Answers

100 votes = 20% of the total votes cast difference % between two candidates.
$therefore$The total number of votes cast = 500

20% is 7.2

$20$

$text{ Increase }$

Population after 3 years

$= 64000 Big(1 + frac{10}{100}Big)^3 = 64000 times frac{1331}{1000}$

Increase = 64000 $times frac{1331}{1000} - 64000$ = 21184

Let cost price = Rs. 100 per kg
= Rs. 100 per 1000 gm
and he use 1 kg as 800 gm.
 $therefore$  His gain = cost of 200 gm = Rs. 20
 $therefore$ His gain  $\mathrm{\%}=\frac{20}{80}\times 100=25\mathrm{\%}$

Percentage increase in salary $= frac{8100 - 7200}{7200} times 100$

$begin{aligned} &= frac{900}{7200} times 100$

Let initial price of cooking gas be Rs. 100.
Price after increase = Rs. 115
On Rs. 115 he should reduce Rs. 15 on Rs. 100, he should reduce

$=frac{15}{100} times 100 = 13frac{1}{23}$

$begin{aligned} & text{Given, } 90$

Amount of milk in tub = 38 liters
 $because$ Tub found to be 5% empty
 $therefore$ Total quantity of milk in per cent = 95%
Now, completely fill the tub, total amount of additional milk

$= frac{38 times 5}{95} = 2 text{ liters}$

$begin{aligned} & =bigg(1 - frac{10}{100} bigg) bigg(1 - frac{10}{100} bigg) \ & = frac{90}{100} times frac{90}{100} = 81$

Let total output be $x$ quintal.
 $therefore$ Useful output = 100 − 24 = 76%

$begin{aligned} & Rightarrow frac{76}{100}x = 68400 & Rightarrow x = frac{68400 times 100}{76} & therefore x = 90000 text{ quintal } end{aligned}$

The price of item first increased by 20% and then decreased by 20%.

$begin{aligned} & therefore text{ Net effect } bigg(20 - 20 + frac{20 times (-20)}{100} bigg) \ &= frac{-400}{100} = -4$

Let total income be $x$
Income deposited $= 10$

$= frac{10}{100} bigg(x - frac{4}{100} x bigg) = frac{96}{1000}x$

$begin{aligned} & text{Remaining income } = text{ Rs. } 10800 & therefore frac{4}{100}x + frac{96x}{1000}+10800 = x & Rightarrow 10800 = x - frac{136x}{1000} ~ & Rightarrow 10800 = frac{864x}{1000} ~ & Rightarrow x = frac{10800 times 1000}{864} ~ & therefore x = text{ Rs. } 12500 end{aligned}$

Let the salary of Rohit be Rs. 100, then saving = Rs. 30
Expenses = Rs. 70
New expenses = (100 + 30)% of Rs. 70 = Rs. 91
New saving = Rs. (100 - 91) = Rs. 9
He saves Rs. 9, his salary = Rs. 100
If he saves Rs. 1215.
Then, his salary = Rs. $bigg(frac{100}{9} times 1215 bigg)$
= Rs. 13500

Amount of sugar in 6 liter of solution
$=frac{4}{100} times 6 = 0.24 text{ Liter}$

After evaporation, sugar in 5 liter = 0.24 liter
 $therefore$ Percentage of Sugar

$= bigg(frac{0.24}{5} times 100 bigg) = 4frac{4}{5}$

Let the third number be $z$.
 $therefore$ First number  $x = frac{(100-30)}{100} times z = frac{7z}{10}$

Second Number $y = frac{(100-40)}{100} times z = frac{6z}{10}$

Difference between first and second number
$= (x - y ) = frac{7z}{10} - frac{6z}{10} = frac{z}{10}$

Hence, the required percent
$= dfrac{frac{z}{10}}{frac{7z}{10}} times 100$